3 years ago

The account balance of each of the three children at the end of the month is shown below

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

Just plot the values onto a normal number line

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2 years ago

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Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11

a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

$hyp^{2} = adj^{2} + opp ^{2} \\opp = \sqrt{hyp^{2} - adj^{2} } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}$

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ $\neq$ 1/cosθ but cscθ = 1/sinθ

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2 years ago