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ki77a [65]
3 years ago
14

{18 • [(25 + 15) ÷ 4] + 25} • 12 + 16 • 3

Mathematics
2 answers:
Gre4nikov [31]3 years ago
7 0
We must use the correct order we know as pemdas.
25 + 15 = 40
{18 * [40 ÷ 4] + 25] * 12 + 16 * 3
40 ÷ 4 = 10
{18 * 10 + 25}  * 12 + 16 * 3
18 * 10 = 180
{180 + 25} * 12 + 16 * 3
180 + 25 = 205
205 * 12 + 16 * 3
205 * 12 = 2460
2460 + 16 * 3
16 * 3 = 48 
2460 + 48 = 2508
So, the answer is 2508
Leviafan [203]3 years ago
3 0
2,508 says my calulator
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aivan3 [116]
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3 years ago
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Given that 5x:9=7:3 calculate the value of x. give your answer in its simplest form.
Hitman42 [59]

\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}

<h3>x = 21/5</h3>

Step-by-step explanation:

<h3>___________________________</h3>

<h3>Given →</h3>

5x:9 = 7:3

<h3>So,</h3>

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8 0
2 years ago
Give the equation for a circle with the given center and radius.Center at (-10, -4), radius = 5A. (x−10)^2+(y−4)^2=25B. (x−4)^2+
BaLLatris [955]

D)(x+10)^2+(y+4)^2=5^2=25

Explanation

Step 1

We know that the general equation for a circle is

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\  \end{gathered}

where

(h,k) is the center of the circel

and r is the radius

then, all we need to do is replace

Let

\begin{gathered} \text{center}\Rightarrow(h,k)\Rightarrow(-10,-4) \\ \text{radius}\Rightarrow r\Rightarrow5 \end{gathered}

replace the values

\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-(-10))^2+(y-(-4))^2=5^2 \\ (x+10)^2+(y+4)^2=5^2=25 \end{gathered}

therefore, the answer is

D)(x+10)^2+(y+4)^2=5^2=25

I hope this helps you

7 0
1 year ago
Daily snowfall in Omaha in January<br> Mode, median or mean?
muminat

Answer:

mean but im guessing as well

Step-by-step explanation:

5 0
3 years ago
The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a
Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{   }\times\text{  m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48  }\times\text{  100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}

Hence, there are 300 students.

a)

\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{  }\times\text{  300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72  students} \end{gathered}

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

8 0
1 year ago
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