We see that each triangle takes up precisely one half of the parallelogram. From this, we see that the area of a triangle is one half the area of a parallelogram, or the area of a parallelogram is two times the area of a triangle
If the length is three times the width and the area of the rectangle is
300
then the length of rectangle is 30m and width be 10m.
Given that the length is three times the width and the area of the rectangle is 300
.
We are required to find the length and breadth of the rectangle.
Area of the rectangle is basically the product of length and breadth.
let the breadth of rectangle be w.
The length of rectangle will be 3w.
Area=Length*Breadth
300=3w*w
300=3
100=
w=+10,-10 but ignore -10 because width cannot be negative.
Length=3w=3*10=30m
Width=w=10m
The area can be written as 3
because the area of rectangle is product of length and breadth.
Hence if the length is three times the width and the area of the rectangle is 300
then the length of rectangle is 30m and width be 10m.
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Line B is incorrect cause he did not do like terms
I seef(x) between 0 to 1 is goes to xfinity but in the negative direction
We can say it is large neagtive numbet when x is between 0 and 1