The point (4,7) is the only one that can be plugged into the equation and work. in this case when 4 is plugged in as X & Y is plugged in at 7 we get that 7=7, which is a true statement.
Answer:
Step-by-step explanation:
Given
Suppose side face have a dimension of l\times l
and width of h
volume 
volume 
Area of side wall is 
Area of top Wall 
Area of bottom 
Cost of bottom wall 
Cost of top wall 
Cost of side walls 
total cost 
differentiate C w.r.t l to get minima or maxima
Dimension of Box is
The multiplicative inverse of -13/14 as in the task content is; -14/13.
<h3>What is the multiplicative inverse of -13/14?</h3>
The multiplicative inverse of a number x is given as; 1/x.
On this same note, it follows that since, the number whose multiplicative inverse is to be found is: -13/14, the multiplicative inverse is; -14/13.
Read more on multiplicative inverse;
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Answer:
The first one is the answer
Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
