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xxMikexx [17]
3 years ago
6

Write 64 in expanded from

Mathematics
1 answer:
lozanna [386]3 years ago
3 0
Um im guessing 60 +4 or sixty four
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Sienna, Rhys, and Micah are all reading the same book for school. Sienna has read 40% as far as Rhys has, and Rhys has read 40%
ruslelena [56]

Based on the fact that Sienna has read 60 pages, we can infer that Micha has read 375 pages of the book.

Sienna has read 40% of what Rhys has read and that corresponds to 60 pages. The number of pages read by Rhys is therefore:

<em>= Number of pages / Percentage read </em>

= 60 / 40%

= 150 pages

The 150 pages read by Rhys is 40% of what Micah has read. Micah has therefore read:

= 150 / 40%

= 375 pages

In conclusion, Micah has read 375 pages.

<em>Find out more at brainly.com/question/2807698.</em>

4 0
2 years ago
Chris made $136 for 8 hours of work.
jasenka [17]

Answer:

17 hours

Step-by-step explanation:

$136/8hr = $17 dollars an hour

$17/hr=$289/t

$17/hr t=$289

t=17 hours

7 0
3 years ago
Read 2 more answers
HELP QUICKLY PLEASE!!! for y = 3x - 2x^2 + 5x^3, show how to find the value for y, when x = 3. please show your work.
Brrunno [24]
All you need to do is plug in 3 wherever you see an x!
y = 3(3) - 2(3)^2 + 5(3)^3
y = 9 - 2(9) + 5(27)
y = 9 - 18 + 135
y = -9 + 135
y = 126
Hope this helps!
7 0
2 years ago
Read 2 more answers
Tell whether 12/8 and 3/6 form a proportion
Rus_ich [418]

Answer:

yes they do.... multiply 3/6 by 3 = 12/8

12/8 multiply by 1/3 = 3/6 or 1/2

Step-by-step explanation:

Don't you dare delete again eupora you are dum

my answer was correct you evil

6 0
2 years ago
Given that f(x) =<br> X + 3<br> 2 <br> a) Find f(2)<br> b) Find f'(x)<br> c) Find f"(12)
joja [24]

Answer:

Step-by-step explanation:

Unclear.  Did you mean f(x) = 2^(x + 3)?  If so, the parentheses are mandatory.

Assuming that f(x) = 2^(x + 3) is correct, then:

a) f(2) = 2^(2 + 3) = 2^5 = 32

b) f'(x) = 2^(x + 3)*(x + 3)' = 2^(x + 3)(1) = 2^(x + 3)

c) f"(x) = 2^(x + 3) (same as in (b)), so that:

   f"(12) = 2^15

8 0
3 years ago
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