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Ahat [919]
3 years ago
11

la1" title=" - \frac{7}{10} -( - \frac{4}{15} ) " alt=" - \frac{7}{10} -( - \frac{4}{15} ) " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0
The answer is highlighted. You have to get rid of the parentheses and change the denominators to make them the same.

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Three roots of a fifth degree polynomial function f(x) are -2, 2, and 4 + i. Which statement describes the number and nature of
Juli2301 [7.4K]

We know that imaginary roots always come in pairs, so we already know 4 solutions

-2, 2, 4 + i and a pair of 4 + i

Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots

So for sure, we will have 3 real roots and 2 imaginary roots

Last option, f(x) has three real roots and two imaginary roots

3 0
4 years ago
Yasmine is serving ice cream with the birthday cake at her party. She has purchased 19 1/2 pints of ice cream. She will serve 3/
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She can serve 26 guests (because 19 1/2 divided by 3/4 is 26) and no ice cream will be left (because 26 is a whole number).
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3 years ago
ANSWER NOW PLEASE MY LOVE I AM ABOUT TO DIE I NEED THIS ANSWER.....
vladimir1956 [14]

Answer:the answer is startfraction 1 over 36 end fraction

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Can u help me pls they are exponents with multiplication and division
Ronch [10]
When there is a multiplication involving exponents, we need to evaluate the numbers and each variables separately. In this case, we have 5 and 4 as the numbers, and w and h for the variables.

When we multiply 5 and 4 we get:
5 \times 4 = 20

For w, we have {w}^{6}, {w}^{4}, w. While we are multiplying the w's, we need to add the exponents together to get the final answer: {w}^{6} \times {w}^{4} \times w = {w}^{11}

For h's, there are {h}^{2}, {h}^{5}, {h}^{4}. When we apply the same thing to h's, we get {h}^{2} \times {h}^{5} \times {h}^{4} = {h}^{11}

For the final step, we need to write all of these together: 20 \times {w}^{11} \times {h}^{11} \: \: or \: \: 20 {w}^{11} {h}^{11} \: \: or \: \: 20 {(wh)}^{11}
3 0
4 years ago
PPLLLLLLLLLLLLLLEEEEEEEEEEEAAAAAAAAAASSSSSSSSSSSSSEEEEEEEEEE<br> Help
STALIN [3.7K]

Answer:

its 35.

Step-by-step explanation:

3 0
3 years ago
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