3
pound of strawberry
Step-by-step explanation:
Given parameters:
Pounds of strawberry picked by Lexi =2 
Pounds of strawberry eaten by Lexi sister = 
Unknown:
Pound of strawberry Lexi's sister ate = ?
Solution:
This is a fraction word problem.
Let pound of strawberry eaten by Lexi's sister = K
We can establish that:
Pound of strawberry eaten by Lexi sister x K = Pound of strawberry picked by Lexi
Mathematically we have:
x K = 2 
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K =
= 
K = 3
pound of strawberry
Answer:

Step-by-step explanation:
Given

Required
Determine the domain of the function
To do this, we need to solve for the vertex, p of the function

Given the the general form of a quadratic function is:

By comparison, we have:

So:




Substitute 1 for p in 



This implies that

The interpretation of this is that;
<em>For every value of p, there's a corresponding value of R.</em>
<em>However, because p indicates price and it's impossible to have a negative price, we can say that the minimum value of p is 0;</em>
Hence, the domain is

4x + 5y = 31
5y = -4x + 31
y = -4/5x + 31/5...the slope here is -4/5. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is 5/4 (see how I flipped the slope and changed the sign)
y = mx + b
slope(m) = 5/4
(-1,-7)...x = -1 and y = -7
now we sub and find b, the y int
-7 = 5/4(-1) + b
-7 = -5/4 + b
-7 + 5/4 = b
-28/4 + 5/4 = b
- 23/4 = b
so ur perpendicular line will be : y = 5/4x - 23/4
Answer:
your answer should be 2 and 1/4ths
Step-by-step explanation
2 and 1/4ths bc 5 is more than 4 and there is already a whole so there for there are going to be 2 wholes then there are still parts left over and its out of 4 and there is only one left over so there for it would be 1/4ths.
Answer:
The bearing of the airport from the plane is 245°
Step-by-step explanation:
The bearing of a point from a location is given by the angle in degrees of rotation from the Northern direction of the location to the direction of the location of the point
The given bearing of the plane from the airport = 65°
Therefore, the direction of the plane from the Northern direction of the airport = 65°
From the Northern direction of the plane, the bearing of the airport = 245°