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STatiana [176]
3 years ago
9

Question is below with the image (WIll mark brainiest if u answer 1st)

Mathematics
2 answers:
wolverine [178]3 years ago
8 0
Yes, an octagon is a regular polygon as the shape has atleast 3 straight sides and formed angles.
miv72 [106K]3 years ago
6 0
Yes it’s a regular polygon I Think
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Please answer the question in the photo, thanks!
belka [17]

Answer:

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right )

We rearrange the fractions as improper  fractions for easier division as follows;

2\dfrac{1}{3}  = \dfrac{7}{3}

-3\dfrac{2}{3} = -\dfrac{11}{3}

Therefore, we have;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

4 0
2 years ago
What is the LCM of 3 and 7
Dima020 [189]

Answer:

The LCM of 3 and 7 is 21.

Step-by-step explanation:

‎‎‎‎‎‎

6 0
3 years ago
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Two 5 inch pulleys are Connected by a untwisted straight belt if the first pulley is turned clockwise at 15 rpms in what directi
lorasvet [3.4K]

Answer:2

Step-by-step explanation:

5 0
3 years ago
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Find the value of the expression
Amiraneli [1.4K]
3m^2+2p^2-15

3(3)^2+2(10)^2-15
3(9)+2(100)-15
21+200-15
206
3 0
3 years ago
A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against th
lys-0071 [83]

Answer:   
 let x=rate of the rowing team in still water 
 x+4=rate of the rowing team with current 
 x-4=rate of the rowing team against current   
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 .. 
 90%2F%28x%2B4%29=10%2F%28x-4%29 
 90x-360=10x+40 
 80x=400 
 x=5  rate of the rowing team in still water=5 mph

4 0
3 years ago
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