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liraira [26]
3 years ago
14

Q) Is there a way to solve this using the quadratic formula?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

10.1 seconds

Step-by-step explanation:

s = 4.9 t² + v₀ t

If s = 500 m and v₀ = 0 m/s:

500 = 4.9 t²

t = 10.1

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Natali [406]
Hey You!

2 11/16 = 2.6875 as a decimal.

That's Your Answer! ^
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3 years ago
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5 0
3 years ago
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In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho
Mekhanik [1.2K]

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be \frac{42}{7} C^{\circ}.


Additionally, this can be solved by equations:

\dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = \dfrac{x \,\textrm{C}^{\circ}}{1 \,\textrm{hour}}

1 \,\textrm{hour} \cdot \dfrac{42 \,\textrm{C}^{\circ}}{7 \,\textrm{hours}} = x \,\textrm{C}^{\circ}

\dfrac{42}{7} \,\textrm{C}^{\circ} = x \,\textrm{C}^{\circ}

\dfrac{42}{7} = x


By using two different methods, we can determine that the change each hour was equal to 42/7 C° per hour.

6 0
3 years ago
Can someone teach me how to answer this? Thanks!
DaniilM [7]

Answer:

\left( fg\right)  \left( x\right)  =2x^3\sqrt[3]{x}\\\\\left( \frac{f}{g} \right)  \left( x\right)  =\frac{2x^{3}}{\sqrt[3]{x} }

Step-by-step explanation:

5 0
2 years ago
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The equation would be b = -a or a = -b

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