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olya-2409 [2.1K]
4 years ago
7

Will mark brainliest if right :)

Mathematics
1 answer:
Ymorist [56]4 years ago
6 0

Option A

Hope this helps! ;)

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Find the equivalent to x^7
MrMuchimi
1/x^-7

It would look more like       1
                                        ------
                                             -7 (as an exponent)
                                          x
3 0
4 years ago
If an angle is 16 degrees less than the measure of its complement. What’s the measure of the angle?
Margarita [4]

x-16+x=180

2x-16=180

2x=196

x=98 degrees

x-16= 82 degrees

Hope this helps!

6 0
4 years ago
Read 2 more answers
1.) Find the equation of the circle with center at (-3, 1) and through the point (2, 13).
Sav [38]

Answer:

the negative is what make it wrong

Step-by-step explanation:

3 0
3 years ago
Plss help ill mark brainlist
disa [49]

Answer:

24

Step-by-step explanation:

I don't really know how to explain sorry qwq

5 0
3 years ago
A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
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