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4 years ago

The circular ring of the fountain has a radius of 9 feet. What is the area of the ring?

Mathematics

1 answer:

zepelin [54]4 years ago

4 0

Answer:

about 254.47

Step-by-step explanation

Circle are equation: pi(r)^2

pi(9)^2 = 254.47

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Find BC please in the picture

tatiyna

B. 25 Km. The measure of BC is 25 km.

The easiest way to solve this problem is using the cosine theorem c = √a²+b²-2ab*cos A.

BC = √AC²+AB²-2(AC)(AB)*cos A

BC = √(21km)²+(14km)²-2(21km)(14km)*cos 89°

BC = √441km²+196km²-588km²*(0.017)

BC =√637km²-10.26km²

BC = √636.74km²

BC = 25.03km ≅ 25

7 0

3 years ago

Which shows the correct method for solving the equation below?<br> 1/3 (y-9) =3

iragen [17]

Answer:

$y=18$

Step-by-step explanation:

we have

$\frac{1}{3}(y-9)=3$

Multiply by $3$ both sides

$3*(\frac{1}{3}(y-9))=3*3$

$(y-9)=9$

Adds $9$ both sides

$(y-9)+9=9+9$

$y=18$

5 0

3 years ago

Read 2 more answers

What is the perimeter of a polygon with vertices at (−2, 1) , (−2, 4) , (2, 7) , (6, 4) , and (6, 1) ?

alekssr [168]

First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
$d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }$
$d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4$
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units

5 0

3 years ago

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Which statement is true? A. ABD DBC by SSS B. ABD DBC by SAS C. ABE DBC by SAS D. ABE CBD by SSS

Bumek [7]

Answer:

D. ABE =CBD by SSS.

Step-by-step explanation:

Given that AB = BD and BE = BC, the lengths of AE and CD are equal to each other. Hence, triangles ABE and BCD are congruent by SSS Theorem. The answer is D.

6 0

3 years ago

What is the expression in radical form? (5ab)3/2

andrew11 [14]

It would be a x/n = n √a^x

Hope this helps

8 0

3 years ago

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