Answer:
y = -5x + 21
Step-by-step explanation:
perpendicular lines have slopes that are negative reciprocals.
The given line has a slope of 1/5, so the perpendicular line will have a slope of -5.
y = -5x + B
-4 = -5(5) + B
B = -4 + 25 = 21
y = -5x + 21
Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
The answer is 5:2 ration, it's already fully simplified
Answer:
x > -6
Step-by-step explanation:
Move 6 to the other side:
0.5x > -3
x > -6
Use Photomath it graphs too