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3 years ago

What does the notation f(2) mean?

Mathematics

2 answers:

rjkz [21]3 years ago

6 0

the output (y-value) when x=2

Liula [17]3 years ago

3 0

The expression "f(x)" means "plug a value for x into a formula f "; the expression does not mean "multiply f and x"! Don't embarrass yourself by pronouncing or thinking of "f(x)" as being "f times x". In notation, the "x" in "f(x)" is called "the argument of the function", or just "the argument".

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Solve for y- 4y−3=5y+2

Anastaziya [24]

Y=−5/8 which is the answer to the equation
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3 years ago

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Need help will mark Brainliest

Svetach [21]

Answer:

250 ft.

Step-by-step explanation:

It seems that you are learning the side-splitter theorem right now. If a line is parallel to one side of the triangle and intersects the other two sides, it divides the side proportionally. From the picture we can tell that the streets are parallel, with a line of intersection. Therefore, we can create the following equation of proportionality:

$\frac{375}{300} = \frac{x}{200}$

Now that we have this equation, we can use the butterfly method to solve for x. We cross multiply:

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Now, all we have to do is isolate the variable to find x:

$75000=300x\\x=250$

Therefore, the distance of Orange Ave between the 3rd St. and 4th St. is 250 ft.

I hope this helps! Please let me know if you have any further questions :)

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2 years ago

15% of what number is 900?

Ugo [173]

Answer:

135

Step-by-step explanation:

15/100 × 900 = 15 × 9 = 135

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How many reading questions do i need to get correct to go up from a 620 to a 700?

TiliK225 [7]

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3 years ago

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

Akimi4 [234]

A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is $\mathbf 0$ . We have

$\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k$

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function $f(x,y,z)$ such that its gradient is equal to the given vector field, $\mathbf f(x,y,z)$ :

$\nabla f(x,y,z)=\mathbf f(x,y,z)$

For this to happen, we need to satisfy

$\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}$

From the first equation, integrating with respect to $x$ yields

$f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)$

Note that $g$ *must* be a function of $y,z$ only.

Now differentiate with respect to $y$ and we have

$f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots$

but this contradicts the assumption that $g(y,z)$ is independent of $x$ . So, the scalar potential function does not exist, and therefore the vector field is not conservative.

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3 years ago