Given :Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game.We need to find the minimum number of games that Enzo could have played to win the same number of tickets.
The minimum number of games that Enzo could have played to win the same number of tickets Will be the least common multiple of 11 and 5.
The factors of 11 and 5 are
11=11x1
5= 5x1
Least common multiply = 11x5=5.
The minimum number of games that Enzo could have played to win the same number of tickets is 55.
<span>7n-2(n+5)< 3n-16 / -3n-16
7n-2(n+5)-3n+16<0
5n-3n-10+16<0
2n-10+16<0
2n+6<0 / -6
2n< -6 / :2
n< -6/2
n< -3
n</span>є(-∞:-3)
Answer:
The answer is D
Step-by-step explanation:
Answer:
B. could become equal to the population mean if proper sampling techniques are employed.
Step-by-step explanation:
If any similarities it does not mean equal.
Answer:
180-n_c
Step-by-step explanation:
Given that the ratio of children to adults is 2:1.
Let 
and 
be the number of children and adults in the school carnival.
So, 
Given that the total number of peoples in the carnival =180
So, 
Now, from equations (i) and (ii), we have
Hence, the number of children in attendance is 120.
