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jeka57 [31]
3 years ago
10

HELP HELP WILL MARK THE BRAINLIEST!!!!!!

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0

Answer:0.75

Step-by-step explanation:

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Tomas and Tasha were hiking at a speed of 3.5 mph. On their way back, they were tired and their speed was 2 mph. How long was th
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 To get the length of the route use the expression for speed,

Distance = Speed × Time

Length of the route is 7 miles.

It's given in the question,

 Speed of Tomas and Tasha initially = 3.5 mph

Therefore, distance travelled by both with the speed of 2 mph one way will be,

 Distance = 3.5t [Here, t = time ]

Speed of both while coming back = 2 mph

And the time taken = t + (1 hour 30 minutes)

                                 = (t + 1.5) hours

Therefore, distance travelled while coming back = Speed × Time

                                                                                  = 2(t + 1.5)

Since, length of the route is same both ways,

3.5t = 2(t + 1.5)

3.5t = 2t + 3

3.5t - 2t = 3

1.5t = 3

t = 2 hours

Now substitute the value of t in the expression to get the distance of the route,

Distance = 3.5t

               = 3.5 × 2

               = 7 miles

 Therefore, route was 7 miles long.

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brainly.com/question/1955818

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What is the answer to this inconsistent equation 2x+y=1 and 4x+2y+3 ?
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(2x+y) * 2 = 4x+2y    |
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3 years ago
Given that pentagon ABCDE ≅ pentagon FGHIJ, find the value of m.
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Thank you for posting your question here at brainly. Feel free to ask more questions.   <span><span>The best and most correct answer among the choices provided by the question is  </span>A. 2 .</span>       <span><span>

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If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

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There are 700 students going on a field trip. Transportation safety states that only 46 students are allowed on each bus. How ma
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