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4 years ago

Find the distance between the points (-6,7) and (0,8)

1 answer:

8 0

We can solve this problem by using the distance formula. The distance formula is: $\sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}}$ We can now put in values and solve.

$\sqrt{(-6-0)^{2} + (7-8)^{2}}$

$\sqrt{36 + 1}$

$\sqrt{37}$

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What’s the interger of -(-10)

Lorico [155]

Answer:

Step-by-step explanation:

A negative number with another negative sign is practically a positive number.

Example: -(-4)

-(-4)

-1 * -4

Question: -(-10)

-(-10)

-1 * -10

10

Answer: 10

7 0

3 years ago

The milligrams of a asprin in a persons body is given by the equation a=500 (3/4)^t where the t is the numbers of hours since th

Anit [1.1K]

Answer: 281.25 milligram

Step-by-step explanation:

Given

Milligrams of aspirin left after t hours is given by

$\Rightarrow a=500(\frac{3}{4})^t$

for $t=2\ hr$

$\Rightarrow a=500(\frac{3}{4})^2\\\Rightarrow a=500\times (0.75)^2=281.25\ \text{milligram}$

3 0

3 years ago

What is the probability of having 53 Mondays in a leap year?

Ronch [10]

Answer:

1/7

Step-by-step explanation:

There are 52 weeks in a year. Each have one Monday. Leap years have a total of 366 days. There are 7 days of the week. Monday is one of them, so it'll be a 1/7 chance.

5 0

4 years ago

The histogram shows the numbers of floors in several tall buildings in New york city A.10 B.11 C.41 D.55

scZoUnD [109]

Answer:

10 buildings

Step-by-step explanation:

Incomplete question: Missing Attachment

I will answer your question with the attached histogram

Required

Determine the number of tall buildings that had more than 60 floors

The histogram can be interpreted as follows:

$\begin{array}{cccccc}{Floors} & {1-20} & {21-40} & {41-60} & {61-80} \ \\ {Buildings} & {10} & {5} & {15} & {10} \ \end{array}$

More than 60 floors is represented with the following group: 61 - 80

The frequency of group 61 - 80 is 10

Hence, 10 buildings had more than 60 floors

3 0

3 years ago

A survey taken of 140 sports fans asked the question: "What is the most you have ever spent for a ticket to a sporting event?" T

Zarrin [17]

The IQR is 150 - 130 = 20. Using the 1.5(IQR) criterion we get 130 -1.5(20) = 100. Since the smallest observation of 85 is smaller than 100, it should be considered an outlier

8 0

4 years ago