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lisov135 [29]
4 years ago
8

Suppose we want to estimate vaccination rates among employees in state government, and we know that our target population is 55

percent male and 45 percent female. Our budget only allows a sample size of 200. We randomly sample 110 males and 90 females. This is an example ofA) simple random sampling.
B) stratified random sampling.
C) cluster sampling.
D) judgment sampling.
Mathematics
1 answer:
Soloha48 [4]4 years ago
7 0

Answer:

The answer is Judgment sampling

Step-by-step explanation:

Judgment sampling also known as judgmental sampling is a form of sampling which is non probability(not every individual has a chance of being included) where sample members are chosen only on the basis of the researcher’s knowledge and judgment.

Judgmental sampling is effective when one feel that other sampling techniques will consume more time and that they have confidence in their knowledge to select a sample for conducting the research. It is also used in situations where the sample selected using other sampling methods need to be approved or filtered

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Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are sum
mrs_skeptik [129]

Answer:

Part a

The probability that the event disk has high shock resistance is 0.86

Part b

The probability that a disk has high scratch resistance given that the disk has high shock resistance is 0.8140

Step-by-step explanation:

(a).

From the given information,

Let A denote the event that a disk has high shock resistance,

and let B denote the event that a disk has high scratch resistance.

                          SHOCK HIGH(A)     SHOCK LOW(A)          TOTAL

SCRATCH  

HIGH(B)               70                               9                                79

RESISTANCE       16                               5                                  21

LOW(B)

TOTAL                86                                 14                                100

Compute P(A).

Therefore, the probability value of the event A is 0.86.

Part a

The probability that the event disk has high shock resistance is 0.86

Explanation | Hint for next step

Based on the given information, the probability that the event disk has high shock resistance is 0.86. That means it is approximately equal to 86%.

Step 2 of 2

(b)

From the given information,

Let A denote the event that a disk has high shock resistance,

and let B denote the event that a disk has high scratch resistance.

 

                      SHOCK HIGH(A)     SHOCK LOW(A)            TOTAL

SCRATCH

HIGH(B)             70                               9                               79

SCRATCH

LOW(B)             16                                 5                               21

TOTAL             86                                15                               100

ComputeP(B/A) = P(A∩B) /P(A)  ;P(A) > 0

P(A∩B)  =70/100

​  =0.70

​  

From the part [a], the probability value of the event A is P(A) =0.86 .

Therefore,

P( {B/A}  = P(A∩B)  /P(A)

​=  0.70 /0.86

​  

=0.8140

​  

Part b

The probability that a disk has high scratch resistance given that the disk has high shock resistance is 0.8140

Explanation | Common mistakes

The disk with high scratch resistance is found to be 81.40% with the condition that the disk with high shock resistance is maintained.

4 0
3 years ago
Solve.<br><br> 4x + 4y = 20<br> 4x + y = -10
Amanda [17]
The way I'd do this is by elimination.  Multiply 4x+y=-10 by -14x+4y=20-4x-y=105y=30y=6
As for x multiply 4x+y=-10 by -4
4x+4y=20-16x-4y=4012x=60
x=5
6 0
4 years ago
Read 2 more answers
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tamaranim1 [39]

Answer:

I would need the dimensions of the window to solve

Step-by-step explanation:

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4 years ago
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Answer:

The third option

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Step-by-step explanation:

Solved on Desmos graphing calculator ;)

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Answer:

3. 9

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4. 3r = 16p 128p = ?r

128/16 = 8x3 = 24

r = ref

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6 0
3 years ago
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