What is the product of x/3 and 6/x when x does not equal 0

Mathematics

1 answer:

Greeley [361]2 years ago

4 0

Answer:

$(\frac{x}{3})(\frac{6}{x})=2$

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have the following multiplication given in the problem above:

$(\frac{x}{3})(\frac{6}{x})$

2. Multiply the numerators and the denominators:

$(\frac{x}{3})(\frac{6}{x})=\frac{6x}{3x}$

3. You can simplify the expression. Then, you have:

$\frac{6x}{3x}=2$

You might be interested in

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$