Answer:
thank you i need that
Step-by-step explanation:
Answer:
3/4
Step-by-step explanation:
Give brainliest if it helped...(:
Let x- intercept represents time
Let y-intercept represents population
Let 1990 represent initial year
Points are (0,14.2)(10,12.4)
slope m= ![\frac{y2-y1}{x2-x1}](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D)
= ![\frac{12.4-14.2}{10-0} =\frac{-1.8}{10} = -0.08](https://tex.z-dn.net/?f=%5Cfrac%7B12.4-14.2%7D%7B10-0%7D%20%3D%5Cfrac%7B-1.8%7D%7B10%7D%20%3D%20-0.08)
General linear equation
y= mx+b --------------(i)
here m is slope and b is intercept
plug the 1st point in equation
14.2= -0.018(0) + b
b=14.2
y= 0.018x + 14.2
replace y with p(t) and x with t
p(t) = -0.018t + 14.2
According to the logarithmic property of base change, the correpta answer is option one or the first.
The logarithmic property of base change says that
loga (b) = logc (b) / logc (a)
Therefore the same property applies to this problem and the correct expression for this question is:
logb (x) / logb (a)
The answer is x= -3. 0.7(-3)-1.4=-3.5