Answer:
Step-by-step explanation:
hopethe answer helped you :)
Answer:
34
Step-by-step explanation:
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
1/27
1/27
125
Step-by-step explanation:
Given that,
a - b = 3
9^(1/2b) /3^a = 3^(2/2b) /3^a
= 3^b/3^a
= 3^(b-a)
= 3^(-3)
= 27^(-1)
= 1/27
27^(1/3b) /9^(1/2a) = 3^(3/3b) /3^(2/2a)
= 3^b/3^a
= 3^(b-a)
= 3^(-3)
= 27^(-1)
= 1/27
125^(1/3a) /25^(1/2b) = 5^(3/3a) /5^(2/2b)
= 5^a/5^b
= 5^(a- b)
= 5^3
= 125
Answer:
its c, y = one eighthx2 + 1
Step-by-step explanation:
