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4vir4ik [10]
3 years ago
12

Can someone help me with this don’t mind the 11 it’s not apart of the problem

Mathematics
1 answer:
scoray [572]3 years ago
4 0

let's firstly convert the mixed fractions to improper fractions and then add.

\bf \stackrel{mixed}{2\frac{7}{10}}\implies \cfrac{2\cdot 10+7}{10}\implies \stackrel{improper}{\cfrac{27}{10}}~\hfill \stackrel{mixed}{8\frac{1}{2}}\implies \cfrac{8\cdot 2+1}{2}\stackrel{improper}{\cfrac{17}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{27}{10}+\cfrac{17}{2}\implies \stackrel{\textit{using an LCD of 10}}{\cfrac{(1)27+(5)17}{10}}\implies \cfrac{27+85}{10}\implies \cfrac{112}{10}\implies \cfrac{56}{5}\implies 11\frac{1}{5}

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80% more then $20.00
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Answer

$36

Step-by-step explanation:

You multiply 0.8 by 20 since 0.8 is also 80% and you get 16. Since you want 80% more than 20 you add together to get $36. Hope it helped!

6 0
3 years ago
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Factor each polynomial. Look for a GCF first
weeeeeb [17]

Answer:

20. x\left(x-6\right)\left(x+8\right)

22. 2\left(x+1\right)\left(x+4\right)

24. 5m\left(m-1\right)\left(m+7\right)

Step-by-step explanation:

20. x^3+2x^{2} -48x

The GCF is x, so you group it out of the equation first.

x(x^{2} +2x-48)

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

?+?=2\\?*?=-48

The two numbers would be -6 and 8. You then differentiate the squares.

x\left(x-6\right)\left(x+8\right)

22. 2x^{2} +10x+8

The GCF is 2, so you must group it out.

2(x^{2} +5x+4)

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

?+?=5\\?*?=4

The two numbers would be 1 and 4. Finally, differentiate the squares.

2\left(x+1\right)\left(x+4\right)

24. 5m^{3} +30m^2-35m

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The two numbers would be -1 and 7. Finally, differentiate the squares.

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7 0
2 years ago
Which of the following is the same formula as A = 6s2 ?
Yuki888 [10]

Answer:

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2 years ago
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LuckyWell [14K]

Answer:

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Step-by-step explanation:

a^{2}+4=6a−1

Step 1: Subtract 6a-1 from both sides.

a^{2}+4−(6a−1)=6a−1−(6a−1)

a^{2}−6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

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(is it helpful rate me according to that

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