I believe the answer is: <span>She made friends with the creature by throwing him a red rubber ball.
Despite its scary features, Cerberus is basically a pet dog that is told to guard the gate. (even though the gate that it protects is the gate of hell rather than the gate of normal household).
So annabeth instinctively think that Cerberus must be bored since He got no friend and attention in that place and play fetch with the ball that </span><span>she stole from the Waterworld gift store.</span>
Old growth forests are often more ecologically valuable because they provide Habitat.
Explanation:
Old growth Trees are the trees that never faced any disturbance or shifting from one place to another. They grow where they were sown without any hurdle. Whereas the second growth forests consists of trees which faced disturbance of either shifting or cutting, etc.
Ecologically, old growth trees are more valuable because they provide habitat. Habitat is the atmosphere or natural environment where organisms or species live. Species make such places their habitat where they can find food, shelter, protection and mates to continue their reproduction process.
The habitats are found in the old growth trees in a range of tree sizes, large logs and trees with hollows. Its easy for organisms to live longer in the trees which encounter no disturbance and the natural environment continue to work.
Learn more about Ecology at:
brainly.com/question/1968849
#LearnWithBrainly
Social security because health care and defense and education is very important to the federal government.
B. Fertile. i believe. no promises
Answer:
Mean of sampling distribution=3.5
Standard error of sampling distribution=0.219
Explanation:
We know that
The average of catching fish per fishing trip=μ=3.5
and
The standard deviation of catching fish per fishing trip= σ=1.2.
We have to find the mean and standard error of sampling distribution of 30 fishing trips i.e. μxbar=? and σxbar=?
Mean of sampling distribution=μxbar=μ=3.5
Standard error of sampling distribution=σxbar=σ/√n
Standard error of sampling distribution=σxbar=1.2/√30
Standard error of sampling distribution=σxbar=1.2/5.4772
Standard error of sampling distribution=σxbar=0.219
Thus, the mean and standard error for a sampling distribution of 30 fishing trips are 3.5 and 0.219.
