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Lady_Fox [76]
3 years ago
7

Jimmy rolled a die 90 times and recored the results. He got a one 15 times, a two 22 times,a three 18 times,a four 11 times,a fi

ve 13 times and a six 11 times. What is the relative frequency for getting a five?​
Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer:

13/90

Step-by-step explanation:

Based on your number, the frequency for getting a five is:

13/90

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What is the simple interest of a note that has a face value of $12,000, a rate of 8%, and a term of 1 year?
Tju [1.3M]

Solution:

Given:

\begin{gathered} P=\text{ \$}12,000 \\ R=8\text{ \%} \\ T=1year \end{gathered}

Using the simple interest formula,

\begin{gathered} I=\frac{PTR}{100} \\ I=\frac{12000\times1\times8}{100} \\ I=\text{ \$}960 \end{gathered}

Therefore, the simple interest is $960.

8 0
2 years ago
Jessica made plans to weave a rectangular jute rug, but she needs to update the plans to change the dimensions of the rug. The o
loris [4]

Answer:

Length of rug in original design is 36 inches .

Width of rug in original design is  60 inches .

The problem says that the new design has length 3x inches longer  and x inches wider than the rug in the original plans .

New length of rug would be 3x inches longer than the original design  which is 36 inches .

Thus new length of rug is  ( 3x + 36  )  inches .

New width of rug is x inches wider than the rug in the original plans which is 60 inches in original plan .

Thus new width of rug is   ( x + 60   )   inches .

Area of rectangle is  Length * Width  

Area of new rug is   ( 3x + 36 ) * ( x + 60 )

We distribute the terms using FOIL method .

( 3x + 36 ) *( x + 60 )  = 3x ( x + 60 ) + 36 ( x + 60 )

                                    =  3x² +  3x * 60  + 36 x  + 36 * 60

                                    =   3x²  + 180 x + 36 x + 2160

    Combining like terms ,  3x² + 216 x + 2160

Thus the area of the rug with the new dimensions is

( 3x + 36) ( x + 60 )  = 3x² + 216 x + 2160 .

7 0
3 years ago
Read 2 more answers
The volume of a rectangular prism is more than 156 cubic inches. The prism has a length of 8 inches and a width of 3 inches. Sel
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Multiply All Of The Numbers Thats What I Think You Should Do!
3 0
4 years ago
En una muestra de 50 restaurantes de comida rápida, la venta media fue de $3.000, y la desviación estándar, $200. El intervalo d
Step2247 [10]

Respuesta:

(2945.411; 3054.589)

Explicación paso a paso:

Dado ;

Tamaño de la muestra, n = 50

Media, xbar = 3000

Desviación estándar, s = 200

Nivel de confianza, Zcrítico al 95% = 1,96

El intervalo de confianza se define como:

Xbar ± margen de error

Margen de error = Zcrítico * s / sqrt (n)

Margen de error = 1,96 * 200 / sqrt (50)

Margen de error = 54.589

Límite inferior = (3000 - 54.589) = 2945.411

Límite superior = (3000 + 54.589) = 3054.589

(2945.411; 3054.589)

8 0
3 years ago
Please help me with geometry
spayn [35]
For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

------------------------------------------------------

For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

------------------------------------------------------

For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

------------------------------------------------------

For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

------------------------------------------------------

For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

------------------------------------------------------

For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

------------------------------------------------------

For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

------------------------------------------------------

For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

------------------------------------------------------

For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

------------------------------------------------------

See the attached image for how the answers match up (take note of the letter labels)

3 0
4 years ago
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