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Tpy6a [65]
2 years ago
5

0.167 (7 repeating) as a fraction. STEP BY STEP!!!

Mathematics
2 answers:
Natali5045456 [20]2 years ago
4 0

Make an equation where x is equal to the decimal:

Equation 1: x = 0.167 ( 7 repeating)

Multiply both sides by 10:

Equation 2: 10x = 1.67 (7 repeating)

Subtract equation 1 from equation 2:

10x = 1.67 - x = 0.167 = 9x = 1.51

Solve for x:

x = 1.51 /9

Eliminate the decimal by multiplying by 100:

x = 151/900

Answer: 151/900

Tpy6a [65]2 years ago
3 0

Answer:

1677 Repeating / 1000

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Step-by-step explanation:

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On tuesday And wednesday , cab fare cost $7.75 total. On Monday and Thursday , cab Fare cost $6.30 on each day. On Friday , cab
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3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
3 years ago
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