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ra1l [238]
2 years ago
6

Given the line segment , state the ratio of the segment partitions as. Be sure to reduce fractions

Mathematics
1 answer:
Effectus [21]2 years ago
4 0

Answer/Step-by-step explanation:

Line segment AB consists of segment AC and segment CB.

AC = 7 cm

CB = 21 cm

The entire segment, AB = 21 + 7 = 28cm

The ratio of the segments partitions can be stated as follows:

Ratio of AC to CB = AC:CB = 7:21 = 1:3 = \frac{1}{3}

AC is ¼ of AB (\frac{1}{1 + 3} = \frac{1}{4})

CB is ¾ of AB (\frac{3}{1 + 3} = \frac{3}{4})

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--  500  divided by  5

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What is the point slope of the line when slope is -4 and the given coordinates are (4,-9)
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The point-slope form of the equation of a straight line is:

y-y_1=m(x-x_1)

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There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o
Anastaziya [24]

P(B/A) is \frac{5}{9} in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

  • P(B|A) is called the "Conditional Probability" of B given A
  • Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
  • The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

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∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

   replacement

- That means red is already occurred when green is happened,

  so it is a "Conditional Probability" of green given red

  P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

   the first draw

∴ P(A) = P(red)

∵ P(red) = \frac{3}{10}

∴ P(A) = \frac{3}{10}

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = \frac{5}{9}

∴ P(B) = \frac{5}{9}

- Find P( A and B)

∴ P(A and B) = ( \frac{3}{10} ) . ( \frac{5}{9} )

∴ P(A and B) = \frac{15}{90}

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = \frac{1}{6}

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = \frac{\frac{1}{6}}{\frac{3}{10}}

- Simplify the fraction

∵ \frac{1}{6} ÷ \frac{3}{10} = \frac{1}{6} × \frac{10}{3} = \frac{10}{18}

- Divide up and down by 2

∴ P(B/A) = \frac{5}{9}

P(B/A) is \frac{5}{9} in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

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