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Pachacha [2.7K]
4 years ago
7

Given that sin(x)=7/11, find cos(90-x). A. 4/11 B. 7/11 C. 11/7 D. 11/4

Mathematics
1 answer:
Contact [7]4 years ago
5 0
Based on the given equation above, get the value of x first so that this value can be substituted to the second equation. Value of x can be obtained by taking the arc sin of 7/11 which gives an answer of 39.52 degrees. Substituting this value to the second equation cos (90-39.52) gives an answer equals to 7/11
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Let f(x) = x^2 + 6 and g(x) = x+8/x . Find ( g o f)(­ -7)
faust18 [17]
One way to approach this is to find (g o f)(x) first and then to replace x by -7:

g( f(x) ) = (x^2+6) + 8/(x^2+6)

Now replace x with -7.  We get:    ( g o f )(-7) = 49+6+8 / (49+6), or
                                                                        = 55 + 8 / 55, or 55 8/55 (ans.)
4 0
3 years ago
Read 2 more answers
Please help I don’t understand.
Lina20 [59]
You can work out c first. That's probably the key to the whole problem.
The adjacent side to a 60o angle is 1/2 the hypotenuse
The hypotenuse in this case = 4 Sqrt(3)
Then c = 1/2 (4 sqrt(3)) 
c = 2 sqrt(3) That means d is not true.

Next work out a.
a is in the same triangle as c and the hypotenuse.
a^2 + c^2 = hypotenuse^2
a = ??
c = 2 sqrt(3)
h = 4 sqrt(3)
a^2 + (2 sqrt(3))^2 = (4 sqrt(3))^2
(sqrt(3))^2 = 3
a^2 + 4 * 3 = 16 * 3
a^2 + 12 = 48
a^2 = 48 - 12
a^2 = 36
a = 6

Now we need to work out d
The side opposite and the side adjacent  are equal when opposite a 45o angle in a right angle triangle
d = 6


The last thing to work out is be
a = 6
d = 6
c = ???

a^2 + d^2 = c^2
6^2 + 6^2 = c^2
c^2 = 72
c = sqrt(72)
c = sqrt(6*6*2)
c = 6 sqrt(2)

The answer should be B??? Check this out.
4 0
3 years ago
0.0417 in standard form?
klasskru [66]


4.17 \times  {10}^{ - 2}
This seems like the answer :)
8 0
4 years ago
30 PTS!! Can someone PLEASE rephrase this? The compass and straightedge is more important in constructing geometric structures t
jek_recluse [69]

Answer:

Step-by-step explanation:

This study investigated three mathematics teachers' construction process of geometric structures using compass and straightedge. The teacher-student-tool interaction was analysed. The study consists of the use of a compass and straightedge by the teachers, the ideas of the teachers about their use, and the observations regarding the learning process during the construction of the geometric structures. A semi-structured interview was conducted with the teachers about the importance of the use of a compass and straightedge to construct geometric structures. It was found that teachers taught compass and straightedge constructions in a rote manner where learning is little more than steps in a process. The study concludes with some suggestions for the use of a compass and straightedge in mathematics classes based on the research results. SUMMARY Purpose and significance: For more than 2,000 years, the way in which geometric structures could be constructed with the help of compasses and straightedges has caught the attention of mathematicians. Nowadays, mathematics curriculums place an emphasis on the use of the compass and straightedge. The compass and straightedge is more important in constructing geometric structures than other drawing tools such as rulers and protractors. Because steps taken with a compass and straightedge cannot be seen at first glance and this situation become a problem for students. However, 'doing compass and straightedge construction early in the course helps students to understand properties of figures'

5 0
4 years ago
Determine the x-intercept of the line whose equation is given:
Rudiy27

Answer:

Green

Step-by-step explanation:

cause blue and red make orange :)

8 0
3 years ago
Read 2 more answers
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