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4 years ago

Bonjour j'ai du mal avec cette exercice c'est un devoirs maison si quelqu'un pourrait m'aider je serai sauver merci d'avance

Mathematics

1 answer:

Taya2010 [7]4 years ago

8 0

Salut!

Voici mes démarches :

50cm × 20cm × 10cm = 10,000cm³

On veut en transporter 300, donc : 300 x 10,000 = 3,000,000cm³

2,60m × 1,56m × 1,84m = 7,46304m³

1m³ = 1,000,000cm³

On peut transporter 7,46304m³, donc : 1,000,000 × 7,46304 = 7,463,040cm³

→ Le volume transportable dans 1 fourgon = 7,463,040cm³

→ On veut transporter 3,000,000cm³

⇒ Donc, on pourrait transporter tous les 300 parpaings en 1 seul voyage <u>SELON CE CRITÈRE</u>.

1 parpaings = 10k

On veut en transporter 300, donc : 10kg × 300 = 3,000kg

1kg = 0.001 tonne

On veut transporter 3,000kg, donc : 0.001 × 3,000 = 3 tonnes

→ La charge maximale pouvant être transportée est de 1,7 tonnes.

→ On veut transporter 3 tonnes.

⇒ Donc, on devra faire 2 voyages, c'est-à-dire 2 allers-retours pour pouvoir arriver à transporter tous les 300 parpaings. → RÉPONSE QUESTION #1

2 allers-retours = 4 x 10km = 40 km

On a donc besoin de louer le fourgon pour 1 jour seulement avec 50km maximum.

Cette option a un tarif de 55€

Le fourgon consomme 8L par 100km.

On parcours 40km, donc: (8 × 40) ÷ 100 = 3,2L

1 Litre de carburant coûte 1,50€, donc 1,50 × 3,2 = 4,80€

55€ + 4,80€ = 59,80€ = Coût total du transport → RÉPONSE QUESTION #2.

Et voilà! J'espère que ça a pu t'aider à mieux comprendre! S'il y a quoi que ce soit fait moi signe! :)

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Read 2 more answers

Mrs. Taylor would like to construct a confidence interval for the number of highlighters that are borrowed and not returned in h

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<h3>What is the margin of error(MOE)?</h3>

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

$\rm MOE = Z\times{\sqrt \dfrac{p(1-p)}{n}\\$

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= (0.68-0.071, 0.68+0.071)

= (0.609, 0.751) or

= (60.9%, 75.1%)

Thus, the confidence interval at a 90% confidence level is (60.9%,75.1%) if in the end of a semester, she loaned 115 highlighters and found that 68% were not returned option (A) is correct.

Learn more about the Margin of error here:

brainly.com/question/13990500

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