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jasenka [17]
3 years ago
12

The area of a rectangle is 64 square centimeters. The rectangle is 4 centimeters wide. How long is the rectangle.

Mathematics
1 answer:
VLD [36.1K]3 years ago
4 0
The Area is the width<span> times the </span>height<span>: A = w x h;
Then, 64 = w x h;
h = 4 + w;
64 = 4w  + w^2;
w^2 + 4w - 64 = 0;
We solve this equation: w1 </span>≈ 6,24 > 0 (okay); w2 ≈ - 10,24 < 0 (not okay);
<span>Finally, h1 </span>≈ 10,24;<span>

</span>
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Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

- 21 = 6(-2) – 9  

- 21 = - 12 – 9  

- 21 = - 21  

L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

- 21 = 6(9) – 9

- 21 = 54 – 9  

- 21 = 45  

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

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