Find the vertex of the quadratic function

Mathematics

1 answer:

Galina-37 [17]1 year ago

8 0

Answer:

(1.5,2.5)

Step-by-step explanation:

f(x) = 2x^2 - 6x + 7

Take the first derivative and set it equal to 0 (the slope is 0 at the vertex)

f'(x) = 4x -6

0 = 4x - 6

4x = 6

x = 3/2 or 1.5

If x = (3/2), then y = 2(3/2)^2 - 6(3/2) + 7

y = 2(9/4) - 18/2 + 7

y = (9/2) - 2

y = 2.5

See attached graph.

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so we draw imaginary lines like in attachment
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triangle
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