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Art [367]
3 years ago
11

Please I need your help with those 4 questions and I will mark you brainliest

Mathematics
2 answers:
Fudgin [204]3 years ago
5 0
1000 12 19 49 is all of them
Mademuasel [1]3 years ago
5 0
(Insert answer here) HOPE THIS HELPS
You might be interested in
a square as 9 inch sides. every side of a pentagon is also 9 inches long. are their perimeters the same? explain your answer.
WARRIOR [948]
The perimeters are not the same because a square has 4 sides if u add up all the sides you'll get 36 and a pentagon has 5 sides add up the sides you'll get 45

6 0
4 years ago
How many cubic blocks of side length 1/7 would it take to fill a rectangular prism with a length, width, and height of 3/7 inch,
wlad13 [49]

Answer:

<em>441</em><em> number of cubic blocks will fill the rectangular prism.</em>

Step-by-step explanation:

Volume of rectangular prism is,

V_{Prism}=\text{Length}\times\text{Width}\times\text{Height}

Putting all the values,

V_{Prism}=\dfrac{3}{7}\times\dfrac{1}{7}\times\dfrac{3}{7}

=\dfrac{3\times1\times3}{7}

=\dfrac{9}{7}\ in^3

Volume of cubic block is,

V_{Cube}=\text{Side}^3

Putting all value,

V_{Cube}=\left(\dfrac{1}{7}\right)^3=\dfrac{1}{343}\ in^3

Number of cubic blocks that can fill the rectangular prism is,

=\dfrac{V_{Prism}}{V_{Cube}}=\dfrac{\frac{9}{7}}{\frac{1}{343}}=\dfrac{9\times 343}{7\times 1}=441

4 0
4 years ago
A store pays $119 for a scooter. The store marks up the price by 40%.
Inessa [10]

Answer:

Step-by-step explanation:

if the store marks up the price by 40%

119*(40/100)=47.60

119+47.60=166.60

5 0
3 years ago
Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

#SPJ1

5 0
2 years ago
As part of the Honolulu Heart Study, a sample group of 100 individuals is selected and a study conducted to see if following a 6
adoni [48]

Answer:

t=\frac{203.8-221.4}{\frac{21.6}{\sqrt{100}}}=-8.148    

The degrees of freedom are given by:  

df=n-1=100-1=99  

and the p value would be given by:

p_v =P(t_{(99)}  

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 221.4 the value of study.

Step-by-step explanation:

Information given

\bar X=203.8 represent the sample mean    

s=21.6 represent the sample standard deviation

n=100 sample size  

\mu_o =221.4 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to verify if the true mean is lower than 221.4, the system of hypothesis would be:  

Null hypothesis:\mu \geq 221.4  

Alternative hypothesis:\mu < 221.4  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{203.8-221.4}{\frac{21.6}{\sqrt{100}}}=-8.148    

The degrees of freedom are given by:  

df=n-1=100-1=99  

and the p value would be given by:

p_v =P(t_{(99)}  

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly less than 221.4 the value of study.

7 0
4 years ago
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