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kolbaska11 [484]
3 years ago
5

Part A create an equation and solve for X:

Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0

Answer:

31

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

Vilka [71]3 years ago
5 0

Answer:

x = 2 degree and unknown angle = 31 degree

Step-by-step explanation:

149 + 13x + 5 =180 degree (being linear pair)

154 + 13x = 180

13x = 180 - 154

x = 26/13

x = 2 degree

unknown angle = 13x + 5

=13*2 + 5

=26 + 5

=31 degree

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What are the restrictions on the domain of g°h?<br><br> X&gt; _____
ololo11 [35]

Answer:x=6

Step-by-step explanation:g o h is a composition function

First we find g o h

g o h is g(h(x))

We plug in h(x) in g(x)

We replace x  with 2x-8 in g(x)

To find domain we look at the domain of h(x) first

Domain of h(x) is set of all real numbers

now we look at the domain of g(h(x))

Negative number inside the square root is imaginary. so we ignore negative number inside the square root

So to find domain we set 2x - 12 >=0   and solve for x

2x - 12 >=0

add both sides by 12

2x >= 12

divide both sides by 2

x > = 6

8 0
2 years ago
Read 2 more answers
The first rule is to add 10, then divide by 2 starting from 2. The second rule is to multiply by 3, then subtract 2 starting fro
julsineya [31]

Answer: (2, 2), (6, 4), (8, 10), (9, 28)

Step-by-step explanation:

The first four ordered pairs using the two sequences are:(2, 2), (6, 4), (8, 10), (9, 28)

The first rule is to add 10, then divide by 2 starting from 2

Add/Divide:

10=2+10=12

2=12÷2=6

Add/divide again:

10=6+10=16

2 = 20÷2 = 10 2=16÷2=8

Add/divide again:

10=8+10=18

2=18÷2=9

5 0
2 years ago
What is the y-value of the vertex of the function f(x) = –(x + 8)(x – 14)? The y-value of the vertex is .
enot [183]
      Best Answer:  <span> y=18x^2+9x+14

y=18(x^2+(1/2)x + 1/16) + 14 - 9/8

y = 18(x + 1/4)^2 + 103/8


For y = a*(x - h)^2 + k, (h, k) the vertex

Your vertex: (- 1/4, 103/8)

Equation of axis of symmetry is x = (x-coordinate of vertex) OR x = - 1/4

y-intercept is y-value when x = 0, y = 14

x-intercept(s) do not exist for this upward opening parabola whose vertex y-value is above the x-axis.

The minimum of the function is the y-value of the vertex, 103/8.
=======================================...

Seems like Dizzle was in too much of a hurry and Jeff just copied Dizzle's answer.

The correct way of doing what dizzle TRIED to do:

For y = a*x^2 + b*x + c, the vertex occurs when x = - b / (2*a)

y=18x^2+9x+14

a = 18
b = 9

- b / (2*a) = - (9) / (2*18) = - 9 / 36 = - 1/4

Take that value for x, evaluate function at that value to get y.
=======================================...
Was so giddy about dizzle's faux pas that I originally did this work. May as well share it:

x-intercept(s) can be found by setting function equal to zero and solving:

y = 18(x + 1/4)^2 + 103/8

0 = 18(x + 1/4)^2 + 103/8

18(x + 1/4)^2 = - 103/8

(x + 1/4)^2 = - 103/144

x + 1/4 = +/- i*sqrt(103)/12

x = - 1/4 +/- i*sqrt(103)/12 OR x = [- 3 +/- i*sqrt(103)] / 12

These are the roots of the equation f(x) = 0

Since the roots are complex, there are no x-intercepts. The function is entirely above the x-axis. </span>
8 0
3 years ago
Read 2 more answers
Find the common difference of the arithmetic sequence 1,-1, -3, ...
frutty [35]
Answer:
-2

Explanation:
The common difference of a sequence is the difference between consecutive terms. To find it, we subtract two consecutive terms.

1, -1, -3

1 and -1 are consecutive terms.
-1-1=-2

Therefore, the common difference is -2.

We can also try the same thing with -3 and -1, since they are also consecutive terms.

-3-(-1)
=-3+1
=-2

I hope this helps! Please comment if you have any questions.
4 0
3 years ago
50 points please help
SashulF [63]

Answer:

What are in the boxes?

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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