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3 years ago

5

Simplify 14 to the 15th power over 14 to the 5th power. 13 110 143 1410

2 answers:

galina1969 [7]3 years ago

5 0

14^15/14^5 = 14^(15-5) = 14^10

hoa [83]3 years ago

4 0

Answer:

4^10

Step-by-step explanation:

What I do is to subtract 15 - 5 and leave the 14 be.

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What is a formula to calculate the area of cross section when the figure is in circular shape

Naddik [55]

Answer:

Area for cross-section is 615.7521601cm

Step-by-step explanation:

area of a circle = πr²

π × radius²

In this question, the radius is 14, so you need to square it giving 196.

Then multiply by π = 615.7521601cm (round if necessary)

7 0

2 years ago

Whats the difference of 89,24&17

STALIN [3.7K]

I interpret the first number to be 89.24, so 84 and 24 hundredths.

The difference would be by how many numbers they differ, so we subtract the smaller from the bigger:

89.24-17=12.24

this would be their difference!

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6 0

3 years ago

Negative 7 square root of 12+(-3)subtracted by 8=

jolli1 [7]

-35.248711306 Hope this helps:)

4 0

3 years ago

Read 2 more answers

1. What is the vertex form of the equation?

sergeinik [125]

1.vertex form is $y=a(x-h)^2+k$

to get into vertex form, complete the square

$y=-x^2+12x-4$

step 1: group x terms

$y=(-x^2+12x)-4$

step 2: factor coefient in front of x^2 term

$y=-1(x^2-12x)-4$

prep for next step: take 1/2 of linear (1st dgree term) and square it

$\frac{-12}{2}=-6$ , $(-6)^2=36$

step 3: add positive and negative of that previous number inside the parenthasees

$y=-1(x^2-12x+36-36)-4$

factor perfect squaer trionmial

$y=-1((x-6)^2-36)-4$

take out that -36 by expansion

$y=-1(x-6)^2+36-4$

$y=-1(x-6)^2+32$

2. factor out the 2

$2(x^2+8x+12)$

what 2 numbers multiply to get 12 and add to get 8?

2 and 6

$2(x+2)(x+6)$

3.

for $ax^2+bx+c=0$

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

in our case

$x^2-7x-6=0$

a=1, b=-7, c=-6

$x=\frac{-(-7) \pm \sqrt{(-7)^2-4(1)(-6)}}{2(1)}$

$x=\frac{7 \pm \sqrt{73}}{2}$

so $x=\frac{7+\sqrt{73}}{2}$ and $x=\frac{7-\sqrt{73}}{2}$

4. remember that $i=\sqrt{-1}$ so $i^2=-1$

treat $i$ as a variable

$(-2i)(8i)=$

$(-2)(i)(8)(i)=$

$(-2)(8)(i)(i)=$

$(-16)(i^2)=$

$(-16)(-1)=$

[tex}16[/tex]

8 0

3 years ago

Read 2 more answers

Can someone help me with this math problem?

arlik [135]

No, it is not a solution to the inequality.

8 0

3 years ago

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