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4 years ago

38 = y/2. What equals y?

Mathematics

2 answers:

yan [13]4 years ago

5 0

38 = y/2.
y = 38 * 2
y = 76

answer
y = 76

Alekssandra [29.7K]4 years ago

3 0

Multiply 2 both side
38*2 = (y/2)*2
76 = Y

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Best estimate of -15/16+-1/2

Paraphin [41]

Answer:-23/16

Step-by-step explanation:

-15/16+-1/2

-15/16-1/2 Lcm of 16 and 2=16

(-15-8)/16

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3 years ago

Consider the equation y = -2x + 5. Create a table of five ordered pairs that satisfy the equation. What is the y-intercept of th

Tatiana [17]

Answer: option d.

Step-by-step explanation:

To create a table of five ordered pairs that satisfy the equation, you need to give values to the variable "x" and substitute these into the function to find the corresponding value of "y":

For $x=-2$

$y = -2(-2) + 5=9$

For $x=-1$

$y = -2(-1) + 5=7$

For $x=0$

$y = -2(0) + 5=5$

For $x=1$

$y = -2(1) + 5=3$

For $x=2$

$y = -2(2) + 5=1$

Then, you can make the table:

x -2 -1 0 1 2

y 9 7 5 3 1

To find the x-intercept, substitute $y=0$ into the function and solve for "x". Then:

$0 = -2x + 5\\\\x=\frac{-5}{-2}\\\\x=\frac{5}2}$

This is: ( $\frac{5}{2}$ , 0)

To find the y-intercept, substitute $x=0$ into the function and solve for "y". Then:

$y= -2(0) + 5\\\\y=5$

This is: (0,5)

6 0

3 years ago

Read 2 more answers

Find the sum 49+50+51+52+...+141+142

gayaneshka [121]

Answer:

8977

Step-by-step explanation:

Hello,

$49+50+51+52+...+141+142\\\\=(48+1)+(48+2)+(48+3)+(48+4)+...+(48+93)+(48+94)\\\\=48\times 94+(1+2+3+4+...+93+94)\\\\=48\times 94 + \dfrac{94\times 95}{2}\\\\=47(48\times 2+95)=47\times 191=8977$

thanks

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3 years ago

Charlie is watching hot air balloons. Balloon A has risen at a 60° angle. Balloon B has risen at an 82 angle. If the distance fr

Karo-lina-s [1.5K]

Step-by-step explanation:

b is the anwser or 1005 so there u go

6 0

3 years ago

Read 2 more answers

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$ . Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$

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3 years ago