The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.
He has 3/5 of his cards left because he had 62/105 of his cards and that simplified is 3/5
good morning,
Answer:
10×(1-0.2ⁿ)
Step-by-step explanation:
1.6/8=0.2
0.32/1.6=0.2
0.064/0.32=0.2
let S represent the sum of n term then S=8×[(1-0.2ⁿ)/(1-0.2)] = 10×(1-0.2ⁿ).
:)
The answer depends on the weight of each individual bag. Do you know exactly how heavy each of the bags are? Please be more clear in your question.
RemarkI take it that you want to know the ratio of the radii. If this is not correct, leave a comment below my answer.
You could do this by giving the spheres a definite volume, like 1 and 8 and then solve for r for one of them and then use the other sphere to find it's radius. It is not exactly the best way, and if you are going to to a physics class you want to be doing this using cancellation.
Step One Set up the Ratio for the volumes.
Step TwoSetup the equation for V1/V2 using the definition for a sphere. V = 4/3 pi r^3
Step ThreeCancel the 4/3 and pi on the top and bottom of the fractions on the right.
You are left with 1/8 = (r1)^3/ (r2)^3
Step FourTake the cube root of both sides.
cube root 1/8 = 1/2
Cube root of (r1)^3 = r1
Cube root of (r2)^3 = r2
Step FiveAnswer
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