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ElenaW [278]
2 years ago
14

For a function f(x), the difference quotient is x + one-half h + 15. Which statement explains how to determine the average rate

of change of f(x) from x = 5 to x = 8? Substitute 5 for x and 3 for h in the expression x + one-half h + 15. Substitute 5 for x and 8 for h in the expression x + one-half h + 15. Substitute 8 for x and 5 for h in the expression x + one-half h + 15. Substitute 8 for x and 3 for h in the expression x + one-half h + 15.
Mathematics
1 answer:
Paraphin [41]2 years ago
8 0

The average rate of change of f(x) from x = 5 to x = 8 would be gotten by; B: Substituting 5 for x and 8 for h in the expression x + one-half h + 15

<h3>How to used difference quotient to find average rate of change?</h3>

The difference quotient is defined as a measure of the average rate of change of a function over an interval.

The limit of the difference quotient which is the derivative is the instantaneous rate of change.

This differential quotient in calculus is usually expressed as;

[f(x + h) - f(x)]/h

We are given the differential quotient as;

f(x) = x + ¹/₂h + 15

Thus, the average rate of change of f(x) from x = 5 to x = 8 would be gotten by;

Substituting 5 for x and 8 for h in the expression x + one-half h + 15

Read more about Difference quotient at; brainly.com/question/18232053

#SPJ1

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the initial term of arithmetic sequence is 5. The eleventh term is 125. what is the common difference of the arithmetic sequence
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An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
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f(11)=125=11m+b
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f(1)=5=1m+b
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120=10m
Divide both sides by 10
12=m
Your common difference is 12.



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