Question

What is the kinetic energy (in j) of an n2 molecule moving at this speed?

Answer 1

1 molecule N2 x (28.0 g / 6.02 x 10^23 molecules) = 4.65 x 10^-23 g = 4.65 x 10^-26 kg/molecule 1. KE = 1/2 m v^2 = 0.5 x 4.65 x 10^-26 kg x (469.4 m/s)^2 = 5.12 x 10^-21 J/molecule 2. ... kinetic energy=(1/2)m*speed^2