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Harrizon [31]
3 years ago
9

Please help me with this question, image attached.

Mathematics
2 answers:
Vlad [161]3 years ago
8 0

The Answer is A

Hope this helped you

Elis [28]3 years ago
4 0

Since the triangles are similar, n : 6 = 5 : 3.

Hence, n = 10.

You might be interested in
Geometry
igomit [66]

If the base is square, and the perimeter is 14.5, that means that each side of the base is 14.5/4=3.625. Since we now know the length and the width, as well as the height which is 16.8, we plug into the formula \frac{lwh}{3}. So, plug in the details \frac{3.625*3.625*16.8}{3} Your answer will be 73.6 cm^3

4 0
3 years ago
Read 2 more answers
Y’all help please!!!
stealth61 [152]
What do you need help with. I am really good in math
5 0
3 years ago
Could you explain to me how to do this ? I do not understand at all
alexandr1967 [171]

Answer:

I believe this is how you do it

Step-by-step explanation:

csc∅tan∅

(1/sin∅)(sin∅/cos∅)

(sin∅)/(sin∅cos∅)

1/(cos∅)

sec∅

csc²∅tan²∅sin∅

1/(sin²∅) * tan²∅ * sin∅

tan²∅/sin²∅ * sin∅

tan²∅/sin∅

5 0
2 years ago
The measure of the supplement of an angle is 60° less than four times the measure of the complement of the angle. Find the measu
LenaWriter [7]

Answer:

140° and 50°

Step-by-step explanation:

The supplement of the angle (180 - x)

The complement of the angle = (90 - x)

(180 -x) = 4(90-x) - 60

180 - x = 360 -4x - 60

180 -x  = 300 - 4x

180 - x + 4x = 300

 180 + 3x = 300

     3x = 120

      x = 40

   

The supplement (180 - x) =  180 - 40 = 140°

The complement (90 - x) =  90 - 40 = 50°

4 0
3 years ago
A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent
siniylev [52]

Answer:

(a) P (p' > 0.25) = 0.

(b) P (0.15 < p' < 0.20) = 0.7784.

(c) P (133 < X < 171) = 0.2205

Step-by-step explanation:

Let <em>p</em> = proportion of business trip that were for  internal company visit.

It is provided that 19% responded that it was for an internal company visit, i.e.

<em>p</em> = 0.19.

A sample of <em>n</em> = 950 business travelers are randomly selected.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Thus, the distribution of \hat p is N (<em>μ</em> = 0.19, <em>σ </em>= 0.013).

(a)

Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (p' > 0.25) = P (Z > 4.62) = 0

*Use a <em>z</em>-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

(b)

Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)

                               = P (Z < 0.77) - P (Z < -3.08)

                               = 0.7794 - 0.0010

                               = 0.7784

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

Compute the proportion of <em>X</em> = 133  and <em>X</em> = 171 as follows:

p' = 133/950 = 0.14

p' = 171/950 = 0.18

Compute the value of P (0.14 < p' < 0.20) as follows:

P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)

                               = P (Z < -0.77) - P (Z < -3.85)

                               = 0.2206- 0.0001

                               = 0.2205

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

7 0
3 years ago
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