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Brrunno [24]
3 years ago
14

In a sample of 138 tables, the average height was found to be 32.6in. with a variance of 2.8. Give a point estimate for the popu

lation variance of the height of the tables. Round your answer to two decimal places, if necessary. Answer
Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

\hat{\sigma}^2 = 2.8  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 138

Average = 32.6 inch

Population variance,

\sigma^2 = 2.8

We have to find a point estimate for the population variance of the height.

The point estimate for the population variance is the population variance itself.

\hat{\sigma}^2 = \sigma^2 = 2.8

Thus, the point estimate of population variance is the population variance that is 2.8.

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Is it not just EF?

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Elden [556K]

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We are given a right triangle with one side length known and an angle know so we can use some trigonometry.

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6 0
3 years ago
Each floor of a doll house is 12.5 inches tall. If the height of the doll house is 75 inches, how many floors does the doll hous
larisa86 [58]
<h2><u>Answer</u><u> </u><u>:</u></h2>

\bigstar\boxed{\large\bf{\leadsto 6\:floors}}

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀

\begin{gathered}\rm{ \underline{ \underline{ \red{Given}}}}\begin{cases}\sf{height\:of\:one\:floor\:of\:dollhouse =12.4\:in} & \\ \\\sf{Height\:of\: dollhouse=75\:in}&\end{cases}\\\\\end{gathered}

<h2><u>To </u><u>find </u><u>:</u></h2>

  • Total number of Floors in dool house

<u>➜</u><u> </u><u>Therefore</u><u> </u><u>,</u><u> </u><u>Total</u><u> </u><u>number</u><u> </u><u>of </u><u>floors</u><u> </u><u>can </u><u>be </u><u>find </u><u>out</u><u> </u><u>by </u><u>dividing</u><u> </u><u>the </u><u>total</u><u> </u><u>height</u><u> </u><u>of </u><u>dollhouse</u><u> </u><u>by </u><u>the </u><u>length</u><u> </u><u>of </u><u>one </u><u>floor</u>

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{=\cancel{ \dfrac{75}{12.5}}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{= 6}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀

8 0
3 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)
Romashka [77]

Answer:

The amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

Step-by-step explanation:

The given function is

f(t)=-\frac{1}{2}\sin (3t-2\pi)      .... (1)

The general form of sine function is

F(t)=A\sin (Bt-C)+D                 ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

A=-\frac{1}{2}

B=3

C=2\pi

D=0

So,

amplitude=|A|=\frac{1}{2}

period=3

\text{phase shift}=\frac{2\pi}{3}

Therefore amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

8 0
3 years ago
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