Answer: NEITHER
Step-by-step explanation:
From the equation of lines given above, to know if relationships exist between the two lines, we must first determine that from their gradients or slopes.
From first equation
2x - y = 5,
y = 2x - 5
Therefore, m₁ = 2
From the second equation
3x - y = 5
y = 3x - 5
Therefore m₂ = 3
Recall, For the two lines to be parallel, m₁ = m₂ , and for the two line to be perpendicular, m₁m₂ = -1
since none fulfilled the conditions stated above, the answer then is
NEITHER
477900 there you go use a calculator next time ;)
Answer:
Step-by-step explanation:
What this question is asking of you is what is the greatest common divisor of 12 and 15. Or, what is the biggest number that divides both 12 and 15.
in order to find this we have to split each number into it's prime components.
for 12 they are 2,2 and 3 (
2
⋅
2
⋅
3
=
12
)
and for 15 they are 3 and 5 (
3
⋅
5
=
15
)
Out of those two groups (2,2,3) and (3,5) the only thing in common is 3, so 3 is the greatest common divisor. That tells us that the greatest number of groups that can exist and have the same number of girls and the same number of boys for each group is 3.
Now to find out how many girls and boys there are going to be in each group we divide the totals by 3, so:
12
3
=
4
girls per group, and
15
3
=
5
boys per group.
(just as a thought exercise, if there were 16 boys, the divisors would have been (2,2,3) and (2,2,2,2), leaving us with 4 groups [
2
⋅
2
] of 3 girls [12/4] and 4 boys [16/4] )
Answer:
C=0
Step-by-step explanation:
