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Step2247 [10]
3 years ago
15

What is the kinetic energy of a jogger with a mass of 65.0 kg traveling at a speed of 2.5 m/s

Mathematics
2 answers:
Alexxandr [17]3 years ago
7 0
KE = 1/2mv^2

KE = 1/2(65)*2.5^2
KE = 32.5*2.5^2

KE = 203.125 Joules

The kinetic energy is equal to <span>203.125 J. </span>
Liono4ka [1.6K]3 years ago
5 0
This should be Physics, but anyways here you go!
Kinetiv Energy formula is:
K.E = \frac{1}{2}mv²

Plug in the given.

K.E =  \frac{1}{2}(65)(2.5)²
       = 203.125 J
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Let's simply look at each conjecture and determine if it's true or false.



A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will always be even. And an even number minus 1 is always odd. Doesn't matter if n is positive or not. So this conjecture is true.



B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.



C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always be odd, regardless of what n is. So this conjecture is true.



D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.



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