This is a right angle triangle problem
drawing a vertical line at from the point where the ramp touches the car park leaves a right angle triangle with the
opposite being 2m
hypothenus being 10m
adjacent unknown
we could use sine
SineO equal to opposite over hypothenus
SineO equal to 2/10
SineO equal to 0.2
O equal to Sine^1(0.2)
O equal to 11 .5
The angle between the ramp and the horizontal is 11.5 degrees
Simplify brackets
2/5(x - 4) = 2x
Simplify 2/5(x - 4) to 2(x - 4)/5
2(x - 4)/5 = 2x
Multiply both sides by 5
2(x - 4) = 10x
Divide both sides by 2
x - 4 = 5x
Subtract x from both sides
-4 = 5x - x
Simplify 5x - x to 4x
-4 = 4x
Divide both sides by 4
-1 = x
Switch sides
<u>x = -1</u>
Answer:
Step-by-step explanation:
![\dfrac 12 \left[\sin(a+b)+\sin(a-b) \right]\\\\\\=\dfrac 12\left[ 2 \sin a \cos b\right]\\\\\\=\sin a \cos b](https://tex.z-dn.net/?f=%5Cdfrac%2012%20%5Cleft%5B%5Csin%28a%2Bb%29%2B%5Csin%28a-b%29%20%5Cright%5D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%2012%5Cleft%5B%202%20%5Csin%20a%20%5Ccos%20b%5Cright%5D%5C%5C%5C%5C%5C%5C%3D%5Csin%20a%20%5Ccos%20b)
The length is 5 because 5 cubed equals 125.
