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choli [55]
3 years ago
8

What does 9 minus x squared equals?

Mathematics
1 answer:
natta225 [31]3 years ago
3 0
9 - x^2
= 3^2 - x^2
= (3+x)(3-x)
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What is the value for angle 2?<br><br> I need help
GaryK [48]

Answer:

120

Step-by-step explanation:

all complementary angles should add up to 180 degrees

4 0
3 years ago
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Is 0.000061 greater than 610,000<br>​
NeTakaya

Answer:

no.

Step-by-step explanation:

0.000061 is a decimal, and the number to the left of the decimal would be a whole number, which is 0. this means the number is less than one.. while 610,000 is a number jn the thousands, making it greater.

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3 years ago
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Round 742396 to
exis [7]

When we round 742396 to four significant digits, then we get the answer of 742400

What we do is circle the first four digits on the left which are the 7,4,2, and 3. That last 3 will bump up to a 4 because we round up to the nearest hundred (due to the next digit being a 9, which is greater than 5).

Put another way, 742396 is closer to 742400 than it is to 742300. The zeros in 742400 are not significant.

---------------------------------------------

When we round 742396 to two significant digits, then we get the answer 740000

This time, we only keep the 7 and the 4 as our two important digits. Everything else becomes a 0 which isn't significant. No rounding happens since the 2 after the 4 isn't larger than five. I.e. the number 742396 is closer to 740000 than it is to 750000

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Rounding 0.07284 to three significant digits gets us to the answer 0.0728

We drop the 4 at the end because the 7,2, and 8 take up the three digits we want to keep. The two zeros are not significant.

---------------------------------------------

Rounding 0.07284 to two significant digits gets us the answer 0.073

We keep the 7 and 2 as our two important digits, but bump that 2 up to a 3 because the next digit over is larger than five.

7 0
2 years ago
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Find the median first quarrile, third quartile, interquartile range, and an outliers for each set of data
Igoryamba
The outlier is 68

The median is 102
First quartile: 87
Third Quartile: 115
The interquartile range is 87-115
3 0
3 years ago
A researchers wants to determine the mean weight of avocados grown in Southern California. The population from which the sample
natka813 [3]

Answer: (0.465, 5.535)

Step-by-step explanation:

Formula to calculate the confidence interval (<em>when population standard deviation is unknown</em>) is given by :-

\overline{x}\pm t_{\alpha/2} \dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean.

s= sample standard deviation.

n= Sample size.

t_{\alpha/2} = critical value

By considering the given information , we have

\overline{x}=6

s=0.75

n= 9

Significance level = \alpha=0.1   [1-0.90=0.1]

By using students' t distribution -table , the critical value for 95% confidence level :

t_{\alpha/2 , n-1}=t_{0.1/2,\ 8}=1.86

[Note: degree of freedom = n-1]

Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :

6\pm (1.86) \dfrac{0.75}{\sqrt{9}}

6\pm (1.86) \dfrac{0.75}{3}

6\pm (1.86) 0.25

6\pm 0.465=(6-0.465,\ 6+0.465)=(0.465,\ 5.535)

Hence, the required confidence interval  =(0.465, 5.535)

4 0
3 years ago
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