Question

If the diastolic blood pressure at the heart level is 80.0 mm Hg, what is the diastolic pressure at the height of the head, which is 0.300 m above the heart? Ignore any pressure drop due to the viscosity of the blood. g

Answer 1

Answer:

56.6 mm of Hg

Explanation:

Given that;

the diastolic blood pressure at the heart level is 80.0 mm Hg = $(P_0)$

height = 0.300 m

the diastolic pressure at the height of the head, which is 0.300 m above the heart can be determined using the formula

P= $(P_0) - (pgh)$

where; $(pgh)$ is the hydrostatic pressure applied by the column of the liquid (Blood) of height (h) and average density $p$, also the g = gravitational acceleration.

the average density $p$ of a human blood = 1060 kg/m³

gravitational acceleration. ( g ) = 9.81 m/s²

h = 0.300 m

∴ the $(pgh)$ = 1060 kg/m³ × 9.81 m/s² × 0.300 m

 = 3119.58 Pascal (Pa)

From the standard conversion rate, 1 mm of Hg(mercury) = 133.322 Pa

∴ the amount of mm of Hg(mercury) that can be gotten from 3119.58 Pascal (Pa) will be; $\frac{3119.58}{133.322}$

= 23.40 mm of Hg(mercury)

P= $(P_0) - (pgh)$

P= (80.0 - 23.4) mm of Hg

P= 56.6 mm of Hg