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jolli1 [7]
3 years ago
10

Help (pic attached!!)

Mathematics
1 answer:
mash [69]3 years ago
7 0
( \sqrt[5]{ 3^{2} } )^{ \frac{1}{3} } =  (3^{ \frac{2}{5} } ) ^{ \frac{1}{3} } = 3^{ \frac{2}{15} }

Answer: C.
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10x +7 = -3х – 3 help guys
Pepsi [2]

Answer:

x = -10/13

Step-by-step explanation:

10x + 7 = -3x - 3

Add 3x to both sides

10x + 3x + 7 = -3x + 3x - 3

13x + 7 = 0x - 3

13x + 7 = -3

Subtract 7 from both sides

13x + 7 - 7 = -3 - 7

13x + 0 = -10

13x = -10

Divide both sides by 13

13x ÷ 13 = -10 ÷ 13

1x = -10/13

x = -10/13

6 0
2 years ago
8 + (-10) just confused lol
grin007 [14]
8+(-10) is like 10-8 except backwards so how i do some problems is like that and then add a negative sign; so say if i were doing 8+(-10), i would do 10-8 which equals 2 and then since 10 is bigger than 8 and it’s a negative number, i would put -2 as my answer
5 0
3 years ago
Id- 6217974205 p/w-123​
andrey2020 [161]

Answer:

For what-

Step-by-step explanation:

huh

7 0
3 years ago
Read 2 more answers
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
Will 4in. 3in. and 5in. form a triangle?
lesya692 [45]
Yes, there is a type of triangle called a "3 4 5 triangle" with side lengths 3, 4, and 5. 
8 0
2 years ago
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