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Gre4nikov [31]
3 years ago
13

Which of the following statements demonstrates the associative property of multiplication?

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
5 0
Here 2 + (3 + 4) = 2 + (4 + 3) represents the Gmmuative property of addiction A+b = b+a
IgorC [24]3 years ago
4 0
2+(3+4)=2+(4+3) that’s the Gmuative property A+B=B+A
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How can you check the correctness of a division answer that has no remainder
gregori [183]
Multiply your outside number and your answer to see if you got the number inside the box
7 0
3 years ago
Shane earns $3 for completing a chore (c) and $2 for completeing his homework (h). In a week, he earns $24 by completing a total
ki77a [65]

Answer:

6 for c and 3 for h

Step-by-step explanation:

6*3+3*2

8 0
2 years ago
Rodrick is visiting the local museum exhibit and has a maximum of $30 dollars to spend. The entry ticket cost $7. He can spend g
valentinak56 [21]

Entry ticket = $7

Gift shop money = $g

Maximum to spend = $30

Inequality => 7+g ≤ 30

Hope it helps!

6 0
2 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
Riley tried the following homework question:
blondinia [14]

Answer:

her balance aka ADB would be 372.08

4 0
2 years ago
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