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Luda [366]
3 years ago
7

If one ray contamine anotaré ray, aré they te sane ray?

Mathematics
1 answer:
Savatey [412]3 years ago
5 0
The rays are considered the same if each ray contains the other. If only one of the rays contains the other, it's not enough.
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What is 3x+4y=16 for x
sergiy2304 [10]
3x + 4y = 16           Write original equation     
3x + 4y - 4y = -4y + 16          Subtract 4y from each side
3x = -4y +16                    Simplify
3x/3 = -4y/3 + 16/3      Divide each side by three
x = -4y/3 +16/3             Simplify

I hope this helps!

4 0
3 years ago
What is the value of x in the equation 4x+8y=40, when y=0.8?
lubasha [3.4K]
4x+8y=40
0.8*8=6.4
4x+6.4=40
40-6.4=33.6
4x=33.6
33.6\4=8.4
X=8.4
6 0
3 years ago
The graph shows the relationship between the volume of a rectangular prism and the volume of a square pyramid with an identical
True [87]

Answer: is it on chart? if count rise over run

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An architect creates a scale model of a building with a scale of 3 inches =11 feet of the actual width of the building is 121 fe
Tomtit [17]

Answer:

The width of the scale model is 33 inches.

Step-by-step explanation:

This question is solved making a relation with the scale model.

In the scale, 3 inches are worth 11 real feet.

The actual width of the building is 121 feet, so we find it's scale by a rule of three.

3 inches - 11 feet

x inches - 121 feet

11x = 121*3

Simplifying by 3, both sides

x = 11*3 = 33

The width of the scale model is 33 inches.

5 0
3 years ago
Find the volume of each figure. Round your answers to the nearest hundredth, if necessary
SCORPION-xisa [38]

Answer:

666.67π .ft^3

<em>here's</em><em> your</em><em> solution</em>

<em>=</em><em>></em><em> </em><em>radius</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ft</em>

<em>=</em><em>></em><em> </em><em>height</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>2</em><em>0</em><em> </em><em>ft</em>

<em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cone </em><em>=</em><em> </em><em>πr^</em><em>2</em><em>h</em><em>/</em><em>3</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>radius</em><em> and</em><em> height</em><em> </em>

<em>=</em><em>></em><em> </em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>^</em><em>2</em><em>*</em><em>2</em><em>0</em><em>/</em><em>3</em><em>π</em>

<em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>6</em><em>6</em><em>6</em><em>.</em><em>6</em><em>7</em><em>π</em><em> </em><em>.</em><em>ft^</em><em>3</em>

<em>hope</em><em> it</em><em> helps</em>

5 0
2 years ago
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