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Luda [366]
3 years ago
7

If one ray contamine anotaré ray, aré they te sane ray?

Mathematics
1 answer:
Savatey [412]3 years ago
5 0
The rays are considered the same if each ray contains the other. If only one of the rays contains the other, it's not enough.
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For f(x)=3x+1 and g(x)=x²-6, find (f-g)(x)
Lorico [155]

The value of (f - g)(x) is -x² + 3x + 7.

<h3>What is Function?</h3>

The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

Here, the given functions are;

   f(x) = 3x + 1

   g(x) = x² - 6

Now,

 (f - g)(x) = f(x) - g(x)

              = (3x + 1) - (x² - 6)

              = 3x + 1 - x² + 6

(f - g)(x)  = -x² + 3x + 7

Thus, the value of (f - g)(x) is -x² + 3x + 7.

Learn more about Function from:

brainly.com/question/12431044

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2 years ago
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5 numbers are listed below. 3.14, 3 2/3, π, √3, 3.11. which shows the list in order from least to greatest​
kykrilka [37]

Answer:

sq rt 3, 3.11, 3.14, Pi, 3 2/3

7 0
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PlEase answer !!<br><br> Will give brainlst
kaheart [24]

solution:

V=πr2h

3=π·9.32·18.4

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3 0
3 years ago
Expressed as a percent, 0.325 is less than 100%. True False
Marianna [84]
True)

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just remember 1.00 is 100%
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For a moving object, the force acting on the object varles directly with the object's acceleration. When a force of 25 N acts on
Radda [10]

\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}

According to the Question,

\large{\sf{ f \propto \: a}}

<h3>From the Question,</h3>

  • Initial Acceleration,a = 5 m/s²

  • Force at a = 5 m/s²,f = 25 N

  • Final Acceleration,A = 9 m/s²

<h3>To find</h3>

Force exerted on the object at a = 9 m/s²

We Know that,

\huge{\boxed{ \boxed{ \sf{f = ma}}}}

Firstly,we need to find the mass of the object

Thus,

\sf{m =  \frac{f}{a} } \\  \\  \implies \:  \sf{m =  \frac{25}{5} } \\  \\  \huge{ \implies \:  \sf{m = 5 \: kg}}

Now,

\sf{F = mA} \\  \\  \implies \:  \sf{F = (5)(9)} \\  \\  \huge{ \implies \:  \sf{F = 45 \: N}}

7 0
3 years ago
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