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ss7ja [257]
2 years ago
9

Plss help me with this:(((​

Mathematics
1 answer:
TEA [102]2 years ago
5 0
  1. <em><u>C</u></em>
  2. <em><u>B</u></em>
  3. <em><u>C</u></em>

<em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em>

<em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on</u></em><em><u> learning</u></em>

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List five numbers that have 3,5 and 7 as prime factors
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<span>Its: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23 </span>
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2 years ago
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dolphi86 [110]

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Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.
SashulF [63]

<u>ANSWER</u>

{r}^{2}  = 4  \cos2\theta

<u>EXPLANATION</u>

The Cartesian equation is

{( {x}^{2}  +  {y}^{2} )}^{2}  = 4( {x}^{2} -  {y}^{2}  )

We substitute

x = r \cos( \theta)

y = r \sin( \theta)

and

{x}^{2}  +  {y}^{2}  =  {r}^{2}

This implies that

{( {r}^{2} )}^{2}  = 4(( { r \cos\theta)  }^{2} -  {(r \sin\theta) }^{2}  )

Let us evaluate the exponents to get:

{r}^{4}  = 4({  {r}^{2} \cos^{2}\theta } -   {r}^{2}  \sin^{2}\theta)

Factor the RHS to get:

{r}^{4}  = 4{r}^{2} ({   \cos^{2}\theta } -   \sin^{2}\theta)

Divide through by r²

{r}^{2}  = 4 ({   \cos^{2}\theta } -   \sin^{2}\theta)

Apply the double angle identity

\cos^{2}\theta -\sin^{2}\theta=  \cos(2 \theta)

The polar equation then becomes:

{r}^{2}  = 4  \cos2\theta

7 0
3 years ago
Plz help me math doesnt like me
marin [14]

Answer:

hello

Step-by-step explanation:

i think diameter is 13 cm

but radius is equal to 13/2=6,5cm

hope it helps

have a nice day

bye

8 0
2 years ago
How do I solve cos x&gt; 1/2 sin x?
Hatshy [7]

Divide both sides by \dfrac12\cos x:

\dfrac{\cos x}{\frac12\cos x}>\dfrac{\frac12\sin x}{\frac12\cos x}\implies2>\dfrac{\sin x}{\cos x}=\tan x

If -\dfrac\pi2, then

\tan x

and more generally, for any integer n,

n\pi-\dfrac\pi2

4 0
2 years ago
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