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3 years ago

Whats ur name, and idk if it will let me but i made it 72 points

Mathematics

2 answers:

Aloiza [94]3 years ago

6 0

Answer:

my name is Emma ^-^

Step-by-step explanation:

valkas [14]3 years ago

5 0

Answer:

my name Alfa

ok ...(っ.❛ ᴗ ❛.)っ

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7w + 6 + 2w = _ (w + 2)

gayaneshka [121]

Answer:

7(-1/2 +2) = -6(2(-1/2) -1) +3(-1/2)

7(3/2) = -6(-2) -3/2

21/2 = 12 -3/2 . . . . . true, answer checks OK

Step-by-step explanation:

3 0

3 years ago

Lolo typed 1125 words in 15 minutes. Let w represent the number of words typed each minute. If Lolo the same number of words eac

Andreas93 [3]

She would type 15 words a minute. you divide 1125 by 15 and you get 15

answer:15

hopes this helps

7 0

4 years ago

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What is the remainder when 12345x54321 is divided by 9

Bas_tet [7]

Answer:

the remainder is 0

Step-by-step explanation:

good luck on the Imc challenge or ukmt however you call it :)

5 0

3 years ago

The number of chocolate chips in an 18-ounce bag of Chips Ahoy! chocolate chip cookies is approximately normally distributed wit

sineoko [7]

Answer:

a) 0.013

b) 0.7

c) 0.866

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1262

Standard Deviation, σ = 118

We are given that the distribution of number of chocolate chips is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(fewer than 1000 chocolate chips)

P(x < 1000)

$P( x < 1000) = P( z < \displaystyle\frac{1000 - 1262}{118}) = P(z < -2.220)$

Calculation the value from standard normal z table, we have,

$P(x < 1000) = 0.013 = 1.3\%$

b) P(contains more than 1200 chocolate chips)

$P(x > 1200) = P(z > \displaystyle\frac{1200-1262}{118}) = P(z > -0.5254)\\\\P( z > -0.5254) = 1 - P(z \leq -0.5254)$

Calculating the value from the standard normal table we have,

$1 - 0.300 = 0.7 = 70\%\\P( x > 1200) = 0.7$

c)P(contains between 1000 and 1400 chocolate chips)

$P(1000 \leq x \leq 1400) = P(\displaystyle\frac{1000 - 1262}{118} \leq z \leq \displaystyle\frac{1400-1262}{118}) = P(-2.22 \leq z \leq 1.169)\\\\= P(z \leq 1.169) - P(z < -2.22)\\= 0.879 - 0.013 = 0.866 = 86.6\%$

$P(1000 \leq x \leq 1400) = 86.6\%$

6 0

3 years ago

What is the solution of the proportion 3/5=13/x ? Round to the nearest tenth if necessary.

Andreyy89

Answer:x=21 2/3

Step-by-step explanation:

6 0

3 years ago

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