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JulsSmile [24]
4 years ago
6

Multiple Choice, could somebody help me with this?

Mathematics
1 answer:
ololo11 [35]4 years ago
3 0

Answer:

option 5 and option 6

Step-by-step explanation:

option 5.

dilate with a scale factor of 1/2.

This is because we have to take as a reference the base circumference of the point p as the problem says, so we see the radius of that circumference is twice that of the other, so to get there it must be multiplied by 1/2

option 6.

reflect in the y-axis.

we can see that the distance of the 2 points to the y axis is the same, which means that it is reflected on the y axis

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Use the Distributive Property to expand the expression. <br><br>0.4(35m - 15n)​
Alenkasestr [34]
=0.4*35 - 0.4*15
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boom
4 0
3 years ago
Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
Arada [10]

Answer:

a) 0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

b) n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

c) n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\hat p=\frac{823}{1000}=0.823

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799

0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79  

And rounded up we have that n=622

Part c

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
Please help ill mark brainliest !
kondor19780726 [428]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Why might algebra tiles not be a good tool to use to factor x² + 18x +80
anyanavicka [17]

Answer:

Algebra tiles would not be a good tool to use to factor because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles and  it would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. and do u have time to drag 80 tiles? lol

Step-by-step explanation:

6 0
4 years ago
Awenser this fast it has to have a greater sign in it
rosijanka [135]

Step-by-step explanation:

25 1/2 = 51/2

1 1/2 = 3/2

51/2 / 3/2 = 17

therefore,

b >15

3 0
3 years ago
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