Answer:
N(24, 3.46)
Step-by-step explanation:
We are given the following in the question:
Percentage of family homes having front poach = 50%
![p = 50\% = 0.50](https://tex.z-dn.net/?f=p%20%3D%2050%5C%25%20%3D%200.50)
Sample size, n = 48
Normal approximation to the given distribution:
![\mu = np = 48(0.50) = 24](https://tex.z-dn.net/?f=%5Cmu%20%3D%20np%20%3D%2048%280.50%29%20%3D%2024)
![\sigma = \sqrt{np(1-p)} = \sqrt{48(0.50)(1-0.50)} = 3.46](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7Bnp%281-p%29%7D%20%3D%20%5Csqrt%7B48%280.50%29%281-0.50%29%7D%20%3D%203.46)
Thus, the distribution of single family homes is best approximated by the normal distribution N(24, 3.46) where mean is 24 and standard deviation is 3.46
43+35=78 the answer is 78